To determine if the point \((-5, 0)\) is a solution to the equation \(y = -x^2 - -6x - 5\), we just need to substitute \(x = -5\) into the equation and check if the result equals \(y = 0\).
The equation can be simplified as follows:
\[ y = -x^2 + 6x - 5 \]
Now, substitute \(x = -5\):
\[ y = -(-5)^2 + 6(-5) - 5 \]
Calculating \((-5)^2\):
\[ (-5)^2 = 25 \]
Now substitute this value back into the equation:
\[ y = -25 + 6(-5) - 5 \]
Calculating \(6(-5)\):
\[ 6(-5) = -30 \]
Now substitute this value back in:
\[ y = -25 - 30 - 5 \]
Now combine these:
\[ y = -25 - 30 - 5 = -60 \]
Since substituting \(x = -5\) gives \(y = -60\), and we wanted to see if it was equal to \(0\), we find that:
\[ y \neq 0 \]
Thus, \((-5, 0)\) is not a solution to the equation \(y = -x^2 + 6x - 5\).