Is (–5, 0) a solution to the equation y = –x2 − –6x − 5?

To determine if the point \((-5, 0)\) is a solution to the equation \(y = -x^2 - -6x - 5\), we just need to substitute \(x = -5\) into the equation and check if the result equals \(y = 0\).

The equation can be simplified as follows:

\[
y = -x^2 + 6x - 5
\]

Now, substitute \(x = -5\):

\[
y = -(-5)^2 + 6(-5) - 5
\]

Calculating \((-5)^2\):

\[
(-5)^2 = 25
\]

Now substitute this value back into the equation:

\[
y = -25 + 6(-5) - 5
\]

Calculating \(6(-5)\):

\[
6(-5) = -30
\]

Now substitute this value back in:

\[
y = -25 - 30 - 5
\]

Now combine these:

\[
y = -25 - 30 - 5 = -60
\]

Since substituting \(x = -5\) gives \(y = -60\), and we wanted to see if it was equal to \(0\), we find that:

\[
y \neq 0
\]

Thus, \((-5, 0)\) is **not** a solution to the equation \(y = -x^2 + 6x - 5\).