To determine if \((-1, -1)\) is a solution to the equation \(y = x^2 - 6\), we need to substitute \(x = -1\) into the equation and see if it equals \(y = -1\).
Starting with the equation:
\[ y = x^2 - 6 \]
Substituting \(x = -1\):
\[ y = (-1)^2 - 6 \]
Calculating \((-1)^2\) gives us:
\[ y = 1 - 6 \]
Now, simplifying:
\[ y = -5 \]
We found \(y = -5\) when \(x = -1\). Since we expected \(y\) to be \(-1\) for the point \((-1, -1)\), we see that:
\[ (-1, -1) \neq (-1, -5) \]
Thus, \((-1, -1)\) is not a solution to the equation \(y = x^2 - 6\).