Is (–1, –1) a solution to the equation y = x2 − 6?

To determine if \((-1, -1)\) is a solution to the equation \(y = x^2 - 6\), we need to substitute \(x = -1\) into the equation and see if it equals \(y = -1\).

Starting with the equation:

\[
y = x^2 - 6
\]

Substituting \(x = -1\):

\[
y = (-1)^2 - 6
\]

Calculating \((-1)^2\) gives us:

\[
y = 1 - 6
\]

Now, simplifying:

\[
y = -5
\]

We found \(y = -5\) when \(x = -1\). Since we expected \(y\) to be \(-1\) for the point \((-1, -1)\), we see that:

\[
(-1, -1) \neq (-1, -5)
\]

Thus, \((-1, -1)\) is **not** a solution to the equation \(y = x^2 - 6\).