Does (6, 1) make the equation y = x2 + –2x true?

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 hour ago

To determine if the point (6, 1) makes the equation \( y = x^2 - 2x \) true, we can substitute \( x = 6 \) into the equation and check if it equals \( y = 1 \).

First, substitute \( x = 6 \) into the equation:

\[
y = 6^2 - 2(6)
\]

Calculating \( 6^2 \):

\[
6^2 = 36
\]

Next, calculate \( -2(6) \):

\[
-2(6) = -12
\]

Now, combine the two results:

\[
y = 36 - 12 = 24
\]

Since \( y = 24 \) when \( x = 6 \), we see that the coordinate \( (6, 1) \) does not satisfy the equation \( y = x^2 - 2x \) because \( 24 \neq 1 \).

Thus, the point (6, 1) does not make the equation true.