Question
Does (1, 6) make the equation y = 5x2 + 8x + 5 true?
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Answered by
GPT-4o mini
To check if the point (1, 6) satisfies the equation \( y = 5x^2 + 8x + 5 \), we will substitute \( x = 1 \) into the equation and see if it equals \( y = 6 \).
1. Substitute \( x = 1 \) into the equation:
\[
y = 5(1^2) + 8(1) + 5
\]
2. Calculate:
\[
y = 5(1) + 8(1) + 5
\]
\[
y = 5 + 8 + 5
\]
\[
y = 18
\]
Now we have \( y = 18 \) when \( x = 1 \), but the point (1, 6) has \( y = 6 \).
Since \( 18 \neq 6 \), the point (1, 6) does not make the equation true.
1. Substitute \( x = 1 \) into the equation:
\[
y = 5(1^2) + 8(1) + 5
\]
2. Calculate:
\[
y = 5(1) + 8(1) + 5
\]
\[
y = 5 + 8 + 5
\]
\[
y = 18
\]
Now we have \( y = 18 \) when \( x = 1 \), but the point (1, 6) has \( y = 6 \).
Since \( 18 \neq 6 \), the point (1, 6) does not make the equation true.
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