Does (1, 6) make the equation y = 5x2 + 8x + 5 true?

To check if the point (1, 6) satisfies the equation \( y = 5x^2 + 8x + 5 \), we will substitute \( x = 1 \) into the equation and see if it equals \( y = 6 \).

1. Substitute \( x = 1 \) into the equation:
\[
y = 5(1^2) + 8(1) + 5
\]

2. Calculate:
\[
y = 5(1) + 8(1) + 5
\]
\[
y = 5 + 8 + 5
\]
\[
y = 18
\]

Now we have \( y = 18 \) when \( x = 1 \), but the point (1, 6) has \( y = 6 \).

Since \( 18 \neq 6 \), the point (1, 6) does not make the equation true.