Does the point (–9, 0) satisfy the equation y = x2 − –8x + –9?

To determine if the point \((-9, 0)\) satisfies the equation \(y = x^2 - (-8x) - 9\), we need to substitute \(x = -9\) into the equation and see if it results in \(y = 0\).

1. Substitute \(x = -9\):
\[
y = (-9)^2 - (-8)(-9) - 9
\]

2. Calculate \((-9)^2\):
\[
(-9)^2 = 81
\]

3. Calculate \(-(-8)(-9)\):
\[
-(-8)(-9) = -72
\]

4. Combine all parts:
\[
y = 81 - 72 - 9
\]

5. Complete the calculation:
\[
y = 81 - 72 = 9
\]
\[
y = 9 - 9 = 0
\]

Since substituting \(x = -9\) results in \(y = 0\), the point \((-9, 0)\) indeed satisfies the equation.

Therefore, the answer is **Yes**.