To determine the rate (or slope) of a line on a graph, you can use the formula:
\[ \text{slope (m)} = \frac{\Delta y}{\Delta x} \]
where \(\Delta y\) is the change in the y-values and \(\Delta x\) is the change in the x-values.
From your description, the line goes from a y-value of 0 to a y-value of -6. Here's how to calculate it:
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Identify the change in y (\(\Delta y\)):
- Final y-value = -6
- Initial y-value = 0
- \(\Delta y = -6 - 0 = -6\)
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Identify the change in x (\(\Delta x\)):
- Since you mentioned it’s a diagonal line and we do not have specific x-values, we'll assume that it moves horizontally from 0 to some value (let's assume it goes from \(x = 0\) to \(x = a\), where \(a\) is the distance of the horizontal movement).
- \(\Delta x = a - 0 = a\)
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Plug these into the slope formula: \[ m = \frac{-6}{a} \]
Since \(a\) is not specified, we cannot give a numerical value for the rate (or slope) without knowing how far the line moves horizontally. However, if we assume the change in x is 1 unit (just for calculation), the slope would then be -6.
So, the rate/slope of the line depends on the horizontal distance it travels. If you provide the specific horizontal movement or x-values, I can give you an exact slope!
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