To determine which point does not belong to the graph of the function \( y = (x + 1)^3 - 2 \), we need to evaluate the function at each x-coordinate of the given points and see if the resulting y-coordinate matches.
1. For the point \((-3, 6)\):
\[
y = (-3 + 1)^3 - 2 = (-2)^3 - 2 = -8 - 2 = -10
\]
Thus, \((-3, 6)\) does not satisfy the function since \(y \neq 6\).
2. For the point \((-3, -10)\):
From the previous calculation, we found:
\[
y = -10
\]
Therefore, this point satisfies the function.
3. For the point \((-2, -3)\):
\[
y = (-2 + 1)^3 - 2 = (-1)^3 - 2 = -1 - 2 = -3
\]
This point also satisfies the function.
4. For the point \((0, -1)\):
\[
y = (0 + 1)^3 - 2 = (1)^3 - 2 = 1 - 2 = -1
\]
This point also satisfies the function.
The point that does not belong to the graph of the function is \((-3, 6)\).