To determine which point does not belong to the graph of the function \( y = (x + 1)^3 - 2 \), we need to evaluate the function at each x-coordinate of the given points and see if the resulting y-coordinate matches.
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For the point \((-3, 6)\): \[ y = (-3 + 1)^3 - 2 = (-2)^3 - 2 = -8 - 2 = -10 \] Thus, \((-3, 6)\) does not satisfy the function since \(y \neq 6\).
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For the point \((-3, -10)\): From the previous calculation, we found: \[ y = -10 \] Therefore, this point satisfies the function.
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For the point \((-2, -3)\): \[ y = (-2 + 1)^3 - 2 = (-1)^3 - 2 = -1 - 2 = -3 \] This point also satisfies the function.
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For the point \((0, -1)\): \[ y = (0 + 1)^3 - 2 = (1)^3 - 2 = 1 - 2 = -1 \] This point also satisfies the function.
The point that does not belong to the graph of the function is \((-3, 6)\).