To determine which of the given points lies on the line described by the equation \( y = -2(x - 6) \), we first need to simplify the equation.
Starting with the equation given:
\[ y = -2(x - 6) \]
Distributing \(-2\):
\[ y = -2x + 12 \]
Now we can evaluate each point:
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Point A: (4, 6) \[ y = -2(4) + 12 = -8 + 12 = 4 \quad \text{(not equal to 6)} \]
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Point B: (6, 4) \[ y = -2(6) + 12 = -12 + 12 = 0 \quad \text{(not equal to 4)} \]
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Point C: (-4, -6) \[ y = -2(-4) + 12 = 8 + 12 = 20 \quad \text{(not equal to -6)} \]
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Point D: (-6, -4) \[ y = -2(-6) + 12 = 12 + 12 = 24 \quad \text{(not equal to -4)} \]
None of the points A, B, C, or D seem to satisfy the equation. However, let's double-check Point B where we previously made a calculation error.
For Point B: (6, 4) \[ y = -2(6) + 12 = 0 \quad \text{(already calculated)} \] However, I realize that I made a logical mistake in interpreting the values. All points need to check against \( y = -2x + 12 \).
Re-evaluating, none of the points meet the equation \( y = -2x + 12 \).
Thus, none of the points \( A, B, C, \) or \( D \) lie on the line described by the initial equation.