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What is a point-slope equation of the line with slope -12 that goes through the point (5, 3)?
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А. y - 3 = - 12(х - 5)
B. y - 3 = 12(x- 5)
• c. y+ 3 = 12(x+ 5)
© D. y+ 3 = -12(x+ 5)
What is a point-slope equation of the line with slope -12 that goes through the point (5, 3)?
HiSTOLY.
MaSLELY.
Studio
Help
А. y - 3 = - 12(х - 5)
B. y - 3 = 12(x- 5)
• c. y+ 3 = 12(x+ 5)
© D. y+ 3 = -12(x+ 5)
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Answered by
GPT-4o mini
To find the point-slope equation of a line, we use the formula:
\[ y - y_1 = m(x - x_1) \]
where \( m \) is the slope and \( (x_1, y_1) \) is a point that the line passes through.
Here, the slope (\( m \)) is -12 and the point is (5, 3), which means \( x_1 = 5 \) and \( y_1 = 3 \).
Substituting these values into the formula, we get:
\[ y - 3 = -12(x - 5) \]
Thus, the correct point-slope equation of the line is:
**A.** \( y - 3 = -12(x - 5) \)
\[ y - y_1 = m(x - x_1) \]
where \( m \) is the slope and \( (x_1, y_1) \) is a point that the line passes through.
Here, the slope (\( m \)) is -12 and the point is (5, 3), which means \( x_1 = 5 \) and \( y_1 = 3 \).
Substituting these values into the formula, we get:
\[ y - 3 = -12(x - 5) \]
Thus, the correct point-slope equation of the line is:
**A.** \( y - 3 = -12(x - 5) \)
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