Question

A movie theater sold 125 tickets for a movie a children's tickets cost $6 in adult ticket cost $12 at the theater sold $1,170 worth of tickets how many adult tickets were sold

Answer 1

Let the number of children's tickets sold be \( x \) and the number of adult tickets sold be \( y \).

From the problem, we know two things:
1. The total number of tickets sold:
\[
x + y = 125
\]
2. The total revenue from the tickets:
\[
6x + 12y = 1170
\]

Now we can solve this system of equations. We can start by rearranging the first equation to express \( y \) in terms of \( x \):
\[
y = 125 - x
\]

Next, we substitute \( y \) into the second equation:
\[
6x + 12(125 - x) = 1170
\]

Expanding this equation:
\[
6x + 1500 - 12x = 1170
\]

Combining like terms:
\[
-6x + 1500 = 1170
\]

Now, isolate \( x \):
\[
-6x = 1170 - 1500
\]
\[
-6x = -330
\]
\[
x = \frac{-330}{-6} = 55
\]

Now that we found \( x \), we can find \( y \):
\[
y = 125 - x = 125 - 55 = 70
\]

Thus, the number of adult tickets sold is \( y = 70 \).

**Final answer:** 70 adult tickets were sold.