Question
what is the irrational square root √28 simplified?
2√7
4√7
2√14
√4 . √7
2√7
4√7
2√14
√4 . √7
Answers
GPT-4o mini
To simplify the square root of 28, we can factor it into its prime factors:
\[
\sqrt{28} = \sqrt{4 \cdot 7}
\]
Next, we can simplify this using the property that \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\):
\[
\sqrt{28} = \sqrt{4} \cdot \sqrt{7}
\]
Since \(\sqrt{4} = 2\), we have:
\[
\sqrt{28} = 2 \cdot \sqrt{7} = 2\sqrt{7}
\]
Therefore, the simplified form of \(\sqrt{28}\) is:
**2√7**
\[
\sqrt{28} = \sqrt{4 \cdot 7}
\]
Next, we can simplify this using the property that \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\):
\[
\sqrt{28} = \sqrt{4} \cdot \sqrt{7}
\]
Since \(\sqrt{4} = 2\), we have:
\[
\sqrt{28} = 2 \cdot \sqrt{7} = 2\sqrt{7}
\]
Therefore, the simplified form of \(\sqrt{28}\) is:
**2√7**