Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
In pea plants, tall plants (T) are dominant over short plants (t). If a heterozygous tall pea plant is crossed with a homozygou...Question
                in plea plants, tall plants (T) are dominant over short plants (t). if a heterozygous tall pea plant is crossed with a homozygous recessive short pea plant, what percentage of the offspring is expected to be tall.
a 25%
b 50%
c 75%
d 0%
            
        a 25%
b 50%
c 75%
d 0%
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To determine the percentage of tall offspring from a cross between a heterozygous tall pea plant (Tt) and a homozygous recessive short pea plant (tt), we can use a Punnett square.
1. The genotypes of the parents are:
- Heterozygous tall (Tt)
- Homozygous recessive short (tt)
2. Set up the Punnett square:
| | T | t |
|-------|-------|-------|
| **t** | Tt | tt |
| **t** | Tt | tt |
3. The possible genotypes of the offspring are:
- Tt (tall)
- tt (short)
4. From the Punnett square:
- 2 out of 4 offspring will be Tt (tall)
- 2 out of 4 offspring will be tt (short)
5. This means that 50% of the offspring are expected to be tall plants.
Therefore, the answer is **b 50%**.
    
1. The genotypes of the parents are:
- Heterozygous tall (Tt)
- Homozygous recessive short (tt)
2. Set up the Punnett square:
| | T | t |
|-------|-------|-------|
| **t** | Tt | tt |
| **t** | Tt | tt |
3. The possible genotypes of the offspring are:
- Tt (tall)
- tt (short)
4. From the Punnett square:
- 2 out of 4 offspring will be Tt (tall)
- 2 out of 4 offspring will be tt (short)
5. This means that 50% of the offspring are expected to be tall plants.
Therefore, the answer is **b 50%**.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.