Question

Q is the midpoint of line segment PM¯¯¯¯¯¯¯¯¯ . Find midpoint Q . (1 point)
Q is located at (0.5,0) . upper Q is located at left parenthesis 0.5 comma 0 right parenthesis . Q is located at (1,−6) . upper Q is located at left parenthesis 1 comma negative 6 right parenthesis . Q is located at (1,0) . upper Q is located at left parenthesis 1 comma 0 right parenthesis . Q is located at (1,6) . upper Q is located at left parenthesis 1 comma 6 right parenthesis .

Answer 1

To find the midpoint Q of a line segment PM, we need the coordinates of points P and M. The midpoint \( Q \) is given by the formula:

\[
Q = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

where \( (x_1, y_1) \) are the coordinates of point P, and \( (x_2, y_2) \) are the coordinates of point M.

Since no specific coordinates for points P and M are provided in your message, I cannot calculate the exact location of Q. However, if you can provide the coordinates of both points P and M, I can help you find the midpoint Q.

Based on the given options:

1. \( (0.5, 0) \)
2. \( (1, -6) \)
3. \( (1, 0) \)
4. \( (1, 6) \)

Without additional information, I cannot determine the correct answer. Could you please provide the coordinates of points P and M?

Answer 2

the coordinates for point P is (1,2) and the coordinates for point M is (1,-2)

Answer 3

Given the coordinates of points P and M:

- Point P: \( (1, 2) \)
- Point M: \( (1, -2) \)

We can find the midpoint Q using the midpoint formula:

\[
Q = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

Substituting the coordinates of P and M:

\[
Q = \left( \frac{1 + 1}{2}, \frac{2 + (-2)}{2} \right)
\]

Calculating each component:

1. For the x-coordinate:
\[
\frac{1 + 1}{2} = \frac{2}{2} = 1
\]

2. For the y-coordinate:
\[
\frac{2 - 2}{2} = \frac{0}{2} = 0
\]

Therefore, the coordinates for the midpoint Q are:

\[
Q = (1, 0)
\]

So the correct answer is \( Q \) located at \( (1, 0) \).