To analyze the chemical reaction \( 2Fe_2O_3 + 3C \rightarrow 4Fe + 3CO_2 \), we need to identify the different elements and count the total number of atoms involved in the reaction.
1. **Identifying Elements:**
- From \( Fe_2O_3 \): Iron (Fe) and Oxygen (O)
- From \( C \): Carbon (C)
- From \( CO_2 \): Carbon (C) and Oxygen (O) (Note: these are already counted)
So, the unique elements in the reaction are:
- Iron (Fe)
- Oxygen (O)
- Carbon (C)
This gives us a total of **3 different elements**.
2. **Counting Total Atoms:**
- **Reactants:**
- \( 2Fe_2O_3 \): Each formula unit has 2 iron atoms and 3 oxygen atoms. Therefore, for 2 formula units:
- Iron: \( 2 \times 2 = 4 \)
- Oxygen: \( 2 \times 3 = 6 \)
- \( 3C \): 3 carbon atoms.
- Total in reactants:
- Iron: 4
- Oxygen: 6
- Carbon: 3
So, total atoms in reactants = \( 4 + 6 + 3 = 13 \).
- **Products:**
- \( 4Fe \): 4 iron atoms.
- \( 3CO_2 \): Each formula unit has 1 carbon atom and 2 oxygen atoms. Therefore, for 3 formula units:
- Carbon: \( 3 \times 1 = 3 \)
- Oxygen: \( 3 \times 2 = 6 \)
- Total in products:
- Iron: 4
- Carbon: 3
- Oxygen: 6
So, total atoms in products = \( 4 + 3 + 6 = 13 \).
Since the totals match, the total number of atoms for the entire reaction is also **13**.
Putting it all together, the results are:
- **Elements: 3**
- **Total Atoms: 13**
Thus, the correct answer is:
**C: Elements: 3; Total Atoms: 13**.