To expand the expression \(-\frac{7}{6}(3g + 2)\), we need to distribute \(-\frac{7}{6}\) to both terms inside the parentheses.
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Distributing to the first term:
\(-\frac{7}{6} \times 3g = -\frac{21}{6}g\) -
Distributing to the second term:
\(-\frac{7}{6} \times 2 = -\frac{14}{6} = -\frac{7}{3}\)
Now, we can combine these results:
\[ -\frac{21}{6}g - \frac{7}{3} \]
We can simplify \(-\frac{21}{6}g\) to \(-\frac{7}{2}g\) (by dividing both the numerator and the denominator by 3):
Thus, the final expanded expression is:
\[ -\frac{7}{2}g - \frac{7}{3} \]
So the correct response is:
negative Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction