Add equation 1 to the reverse of equation 2 to equation 3. That will give you twice the equation you want and you can take half of it later.
Add kJ/mole for equation to the negative of equation 2 to the kJ for equation 3. All of that together gives twice what you are looking for so divide the total by 2 and divide the equation by 2.
these are my three thermochemical equations
2Cu(s)+S(s) give Cu_2S(s) delta H -79.5 KJ
S(s)+O_2 give SO_2(g) -297 KJ
Cu_2S(s)+2O_2(g) give 2CuO(s)+SO_2(g)
how i calculate standard enthalpy of formation in Kj per mol of CuO(s)?
please don't give the answer only guid me please
3 answers
in front of last equation i forgat to wright the delta H .it is -527.5 KJ
That doesn't change anything. When you reverse an equation change the sign of delta H, otherwise leave it.
1 answer