Question
Original
TTC
AAG
Mutation 1
ATC
UAG
Mutation
Mutation 3
TCC
AGG
DNA codon mRNA codon
AAA
The table shows a DNA sequence and three types of mutations that can change the DNA sequence. Which mutation will cause translation to stop?
Mutations 1, 2, and 3
Mutation 1 only
Mutation 1 and 3 only
Mutation 2 only
TTC
AAG
Mutation 1
ATC
UAG
Mutation
Mutation 3
TCC
AGG
DNA codon mRNA codon
AAA
The table shows a DNA sequence and three types of mutations that can change the DNA sequence. Which mutation will cause translation to stop?
Mutations 1, 2, and 3
Mutation 1 only
Mutation 1 and 3 only
Mutation 2 only
Answers
Answered by
GPT-4o mini
To determine which mutation will cause translation to stop, we need to identify the resulting codons after the mutations. Specifically, we are looking for a change to a stop codon.
In the genetic code, the following are stop codons:
- UAA
- UAG
- UGA
Looking at the mutations you provided:
1. **Original DNA codon sequence**: TTC → translates to mRNA codon AAG (which codes for the amino acid Lysine).
- **Mutation 1**: ATC → UAG (which is a stop codon)
- **Mutation 2**: Not provided but not needed for our analysis.
- **Mutation 3**: TCC → AGG (which codes for the amino acid Arginine).
From the comparison:
- **Mutation 1** results in UAG (stop codon), which causes translation to stop.
- **Mutation 3** results in AGG (which does not cause a stop).
Since Mutation 1 leads to the creation of a stop codon, **the correct answer is: Mutation 1 only**.
In the genetic code, the following are stop codons:
- UAA
- UAG
- UGA
Looking at the mutations you provided:
1. **Original DNA codon sequence**: TTC → translates to mRNA codon AAG (which codes for the amino acid Lysine).
- **Mutation 1**: ATC → UAG (which is a stop codon)
- **Mutation 2**: Not provided but not needed for our analysis.
- **Mutation 3**: TCC → AGG (which codes for the amino acid Arginine).
From the comparison:
- **Mutation 1** results in UAG (stop codon), which causes translation to stop.
- **Mutation 3** results in AGG (which does not cause a stop).
Since Mutation 1 leads to the creation of a stop codon, **the correct answer is: Mutation 1 only**.
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