Question

Two tables were generated to compare the functions f(x)
and g(x)=f(x)−1
. Find the missing value in the table for the function g(x)
.(1 point)


x
f(x)
0 0
−1
1
2 4

x
g(x)
0 −1
−1
2 3

Answer 1

To find the missing value in the table for the function \( g(x) = f(x) - 1 \), we need to use the values from the first table for \( f(x) \).

From the first table:

- When \( x = 0 \), \( f(0) = 0 \)
- When \( x = 1 \), \( f(1) = 1 \)
- When \( x = 2 \), \( f(2) = 4 \)

Now, we can calculate \( g(x) \) for each corresponding \( x \):

1. **For \( x = 0 \)**:
\[
g(0) = f(0) - 1 = 0 - 1 = -1
\]

2. **For \( x = 1 \)** (this is where we find the missing value):
\[
g(1) = f(1) - 1 = 1 - 1 = 0
\]

3. **For \( x = 2 \)**:
\[
g(2) = f(2) - 1 = 4 - 1 = 3
\]

Now we can summarize the values of \( g(x) \):

- \( g(0) = -1 \)
- \( g(1) = 0 \) (the missing value)
- \( g(2) = 3 \)

Thus, the missing value in the table for \( g(x) \) when \( x = 1 \) is **0**.