To compute the mean and standard deviation of the given discrete probability distribution, we will use the formulas for the mean (expected value) and standard deviation.
(a) Mean Calculation
The mean \( \mu \) of a discrete random variable is calculated using the formula:
\[ \mu = \sum (x \cdot p(x)) \]
Where \( x \) is the value of the random variable and \( p(x) \) is the probability of \( x \).
Given the data:
- \( x = -9, p(x) = 0.11 \)
- \( x = -7, p(x) = 0.24 \)
- \( x = 0, p(x) = 0.26 \)
- \( x = 3, p(x) = 0.25 \)
- \( x = 5, p(x) = 0.14 \)
Calculating the mean:
\[ \mu = (-9 \cdot 0.11) + (-7 \cdot 0.24) + (0 \cdot 0.26) + (3 \cdot 0.25) + (5 \cdot 0.14) \]
Calculating each term:
- \( -9 \cdot 0.11 = -0.99 \)
- \( -7 \cdot 0.24 = -1.68 \)
- \( 0 \cdot 0.26 = 0 \)
- \( 3 \cdot 0.25 = 0.75 \)
- \( 5 \cdot 0.14 = 0.70 \)
Now summing them up:
\[ \mu = -0.99 - 1.68 + 0 + 0.75 + 0.70 = -1.22 \]
So, the mean is:
\[ \mu = -1.220 \]
(b) Standard Deviation Calculation
The standard deviation \( \sigma \) is calculated using the formula:
\[ \sigma = \sqrt{\sum (x - \mu)^2 \cdot p(x)} \]
First, we need the variance, which is:
\[ \sigma^2 = \sum (x - \mu)^2 \cdot p(x) \]
Calculating each term \( (x - \mu)^2 \):
-
For \( x = -9 \): \[ (-9 - (-1.22))^2 = (-7.78)^2 = 60.7284 \] Contribution to variance: \( 60.7284 \cdot 0.11 = 6.679124 \)
-
For \( x = -7 \): \[ (-7 - (-1.22))^2 = (-5.78)^2 = 33.4084 \] Contribution to variance: \( 33.4084 \cdot 0.24 = 8.049816 \)
-
For \( x = 0 \): \[ (0 - (-1.22))^2 = (1.22)^2 = 1.4884 \] Contribution to variance: \( 1.4884 \cdot 0.26 = 0.387004 \)
-
For \( x = 3 \): \[ (3 - (-1.22))^2 = (4.22)^2 = 17.8084 \] Contribution to variance: \( 17.8084 \cdot 0.25 = 4.4521 \)
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For \( x = 5 \): \[ (5 - (-1.22))^2 = (6.22)^2 = 38.6884 \] Contribution to variance: \( 38.6884 \cdot 0.14 = 5.414416 \)
Summing these contributions to variance:
\[ \sigma^2 = 6.679124 + 8.049816 + 0.387004 + 4.4521 + 5.414416 \approx 24.98246 \]
Now, take the square root to find the standard deviation:
\[ \sigma = \sqrt{24.98246} \approx 4.998 \]
Final Answers
(a) Mean \( \mu \) = -1.220
(b) Standard deviation \( \sigma \) = 4.998