Question
Which is the complementary mRNA strand from the following DNA template?
TTC AGC
(1 point)
Responses
CCU GAU
CCU GAU
AAG TCG
AAG TCG
AAG UCG
AAG UCG
CCT GAT
TTC AGC
(1 point)
Responses
CCU GAU
CCU GAU
AAG TCG
AAG TCG
AAG UCG
AAG UCG
CCT GAT
Answers
Answer
In pea plants, tall plants (T) are dominant over short plants (t). If a heterozygous tall pea plant is crossed with a homozygous recessive short pea plant, what percentage of the offspring is expected to be tall.
(HINT: use a Punnett square to help you with this question)
(1 point)
Responses
25%
25%
75%
75%
0%
0%
50%
(HINT: use a Punnett square to help you with this question)
(1 point)
Responses
25%
25%
75%
75%
0%
0%
50%
Answer
If a black chicken (BB) is crossed with a white chicken (WW) and incomplete dominance is observed, what are the expected phenotypes of the offspring?(1 point)
Responses
All black
All black
All red
All red
All white
All white
All gray
Responses
All black
All black
All red
All red
All white
All white
All gray
Answer
In cattle, coat color is controlled by codominant alleles. A red-coated cow (RR) is crossed with a white-coated bull (WW). What are the expected phenotypes of the offspring?(1 point)
Responses
All red coat
All red coat
All pink coat
All pink coat
All white coat
All white coat
Red and white coat
Responses
All red coat
All red coat
All pink coat
All pink coat
All white coat
All white coat
Red and white coat
Answer
Complete the mRNA sequence that will be formed from the DNA sequence below, then identify the amino acids using the codon chart provided above.
(6 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
TAC CGC CCC
mRNA Response area Response area Response area
Amino Acid Response area Response area Response area
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Answer
Label the parts of DNA in the image below, using the word bank provided. The parts you will label are the blue, pink, and yellow structures only.(3 points)
answers
phosphate group
ribose
codon
deoxyribose
amino acid
base
answers
phosphate group
ribose
codon
deoxyribose
amino acid
base
Answered by
GPT-4o mini
To determine the complementary mRNA strand from the given DNA template, we first need to look at the base pairing rules between DNA and RNA. In RNA, adenine (A) pairs with uracil (U) instead of thymine (T), which is found in DNA. The complementary pairs are as follows:
- A (adenine) pairs with U (uracil)
- T (thymine) pairs with A (adenine)
- C (cytosine) pairs with G (guanine)
- G (guanine) pairs with C (cytosine)
Given the DNA template strand: **TTC AGC**
We will replace each base according to the rules:
- T → A
- T → A
- C → G
- A → U
- G → C
- C → G
Thus:
- TTC AGC
- becomes
- AAG UCG
So the correct complementary mRNA strand is **AAG UCG**.
The correct response is:
**AAG UCG**
- A (adenine) pairs with U (uracil)
- T (thymine) pairs with A (adenine)
- C (cytosine) pairs with G (guanine)
- G (guanine) pairs with C (cytosine)
Given the DNA template strand: **TTC AGC**
We will replace each base according to the rules:
- T → A
- T → A
- C → G
- A → U
- G → C
- C → G
Thus:
- TTC AGC
- becomes
- AAG UCG
So the correct complementary mRNA strand is **AAG UCG**.
The correct response is:
**AAG UCG**
Answered by
GPT-4o mini
To determine the expected percentage of tall offspring from a cross between a heterozygous tall pea plant (Tt) and a homozygous recessive short pea plant (tt), we can use a Punnett square.
1. **Genotypes of the parents**:
- Parent 1 (heterozygous tall): Tt
- Parent 2 (homozygous short): tt
2. **Setting up the Punnett Square**:
```
T | t
-----------------------
t | Tt | tt
-----------------------
t | Tt | tt
```
3. **Offspring Genotypes**:
- Tt (tall)
- tt (short)
4. **Counting the phenotypes**:
- Tt (tall) = 2
- tt (short) = 2
From the Punnett square, we see that there are 2 Tt (tall) offspring and 2 tt (short) offspring out of a total of 4 offspring.
5. **Percentage of tall offspring**:
- \( \text{Percentage of tall plants} = \frac{\text{Number of tall offspring}}{\text{Total offspring}} \times 100 = \frac{2}{4} \times 100 = 50\% \)
Therefore, **50%** of the offspring are expected to be tall.
The correct response is:
**50%**
1. **Genotypes of the parents**:
- Parent 1 (heterozygous tall): Tt
- Parent 2 (homozygous short): tt
2. **Setting up the Punnett Square**:
```
T | t
-----------------------
t | Tt | tt
-----------------------
t | Tt | tt
```
3. **Offspring Genotypes**:
- Tt (tall)
- tt (short)
4. **Counting the phenotypes**:
- Tt (tall) = 2
- tt (short) = 2
From the Punnett square, we see that there are 2 Tt (tall) offspring and 2 tt (short) offspring out of a total of 4 offspring.
5. **Percentage of tall offspring**:
- \( \text{Percentage of tall plants} = \frac{\text{Number of tall offspring}}{\text{Total offspring}} \times 100 = \frac{2}{4} \times 100 = 50\% \)
Therefore, **50%** of the offspring are expected to be tall.
The correct response is:
**50%**
Answered by
GPT-4o mini
In the case of incomplete dominance, the phenotypes of the offspring are a blend of the parent phenotypes.
Given:
- Black chicken genotype: **BB**
- White chicken genotype: **WW**
When these two chickens are crossed, the offspring will inherit one allele from each parent:
- The genotype of the offspring will be **BW** (one black allele and one white allele).
In incomplete dominance, the heterozygous phenotype (BW in this case) is a blend of the two parental traits. Therefore, black (BB) and white (WW) chickens will result in:
- **BW** offspring that exhibit a gray phenotype (a mix of black and white).
Thus, the expected phenotype of the offspring from this cross is:
**All gray**.
The correct response is:
**All gray**.
Given:
- Black chicken genotype: **BB**
- White chicken genotype: **WW**
When these two chickens are crossed, the offspring will inherit one allele from each parent:
- The genotype of the offspring will be **BW** (one black allele and one white allele).
In incomplete dominance, the heterozygous phenotype (BW in this case) is a blend of the two parental traits. Therefore, black (BB) and white (WW) chickens will result in:
- **BW** offspring that exhibit a gray phenotype (a mix of black and white).
Thus, the expected phenotype of the offspring from this cross is:
**All gray**.
The correct response is:
**All gray**.
Answered by
GPT-4o mini
In cattle, coat color being controlled by codominant alleles means that both alleles in a heterozygous individual are fully expressed.
Given:
- Red-coated cow genotype: **RR**
- White-coated bull genotype: **WW**
When these two are crossed, the genotypes of the offspring will be:
- All offspring will be heterozygous **RW** (one red allele from the cow and one white allele from the bull).
Since the alleles are codominant, in the offspring, both coat colors will be expressed fully. Therefore, the expected phenotype for the offspring will be:
- **Red and white coat** (the coat will exhibit both red and white patches).
Thus, the correct response is:
**Red and white coat.**
Given:
- Red-coated cow genotype: **RR**
- White-coated bull genotype: **WW**
When these two are crossed, the genotypes of the offspring will be:
- All offspring will be heterozygous **RW** (one red allele from the cow and one white allele from the bull).
Since the alleles are codominant, in the offspring, both coat colors will be expressed fully. Therefore, the expected phenotype for the offspring will be:
- **Red and white coat** (the coat will exhibit both red and white patches).
Thus, the correct response is:
**Red and white coat.**
Answered by
GPT-4o mini
To complete the process, we need to transcribe the given DNA sequence into mRNA and then translate that mRNA into amino acids.
1. **Given DNA Sequence:** TAC CGC CCC
2. **Transcription to mRNA:**
- The base pairing rules dictate that A pairs with U (in RNA), T pairs with A, C pairs with G, and G pairs with C.
- Therefore:
- T (from DNA) → A (in mRNA)
- A (from DNA) → U (in mRNA)
- C (from DNA) → G (in mRNA)
- C (from DNA) → G (in mRNA)
- G (from DNA) → C (in mRNA)
- C (from DNA) → G (in mRNA)
- C (from DNA) → G (in mRNA)
So the mRNA sequence is:
- **AUG CGC GGG**
3. **Translation to Amino Acids:**
- Now we will use the mRNA codons to find the corresponding amino acids using a codon chart:
- AUG → Methionine (Met)
- CGC → Arginine (Arg)
- GGG → Glycine (Gly)
Putting this together, here are the responses:
- **mRNA:** AUG CGC GGG
- **Amino Acids:** Met Arg Gly
Fill in the responses based on this information:
### mRNA:
- **Response 1:** AUG
- **Response 2:** CGC
- **Response 3:** GGG
### Amino Acid:
- **Response 1:** Met
- **Response 2:** Arg
- **Response 3:** Gly
1. **Given DNA Sequence:** TAC CGC CCC
2. **Transcription to mRNA:**
- The base pairing rules dictate that A pairs with U (in RNA), T pairs with A, C pairs with G, and G pairs with C.
- Therefore:
- T (from DNA) → A (in mRNA)
- A (from DNA) → U (in mRNA)
- C (from DNA) → G (in mRNA)
- C (from DNA) → G (in mRNA)
- G (from DNA) → C (in mRNA)
- C (from DNA) → G (in mRNA)
- C (from DNA) → G (in mRNA)
So the mRNA sequence is:
- **AUG CGC GGG**
3. **Translation to Amino Acids:**
- Now we will use the mRNA codons to find the corresponding amino acids using a codon chart:
- AUG → Methionine (Met)
- CGC → Arginine (Arg)
- GGG → Glycine (Gly)
Putting this together, here are the responses:
- **mRNA:** AUG CGC GGG
- **Amino Acids:** Met Arg Gly
Fill in the responses based on this information:
### mRNA:
- **Response 1:** AUG
- **Response 2:** CGC
- **Response 3:** GGG
### Amino Acid:
- **Response 1:** Met
- **Response 2:** Arg
- **Response 3:** Gly
Answered by
GPT-4o mini
To label the parts of DNA, let's identify the structures typically found in a DNA molecule:
1. **Phosphate Group**: This is the part of the DNA molecule that connects to the sugar and forms the backbone of the DNA structure. It is usually depicted in a structural diagram as a circle or a phosphate group structure.
2. **Deoxyribose**: This is the sugar found in DNA. It is typically shown as a pentose sugar (five carbon atoms) in diagrams.
3. **Base**: This refers to the nitrogenous bases (adenine, thymine, cytosine, guanine) that pair together to form the rungs of the DNA ladder.
Given the word bank provided and the typical colors used to represent structures in DNA:
- **Blue Structures** might usually represent the **phosphate group**.
- **Pink Structures** would typically denote the **deoxyribose** sugar.
- **Yellow Structures** usually represent the **base**.
Here’s how you would label them based on these common conventions:
- **Blue Structure**: **Phosphate group**
- **Pink Structure**: **Deoxyribose**
- **Yellow Structure**: **Base**
If your image follows a different color convention or structure, please adjust the labels accordingly based on the colors in the image you're using!
1. **Phosphate Group**: This is the part of the DNA molecule that connects to the sugar and forms the backbone of the DNA structure. It is usually depicted in a structural diagram as a circle or a phosphate group structure.
2. **Deoxyribose**: This is the sugar found in DNA. It is typically shown as a pentose sugar (five carbon atoms) in diagrams.
3. **Base**: This refers to the nitrogenous bases (adenine, thymine, cytosine, guanine) that pair together to form the rungs of the DNA ladder.
Given the word bank provided and the typical colors used to represent structures in DNA:
- **Blue Structures** might usually represent the **phosphate group**.
- **Pink Structures** would typically denote the **deoxyribose** sugar.
- **Yellow Structures** usually represent the **base**.
Here’s how you would label them based on these common conventions:
- **Blue Structure**: **Phosphate group**
- **Pink Structure**: **Deoxyribose**
- **Yellow Structure**: **Base**
If your image follows a different color convention or structure, please adjust the labels accordingly based on the colors in the image you're using!
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