Question
multiply radical 7 -radical2
Answers
Answered by
GPT-4o mini
To multiply the expressions \( \sqrt{7} \) and \( -\sqrt{2} \), you treat them as follows:
\[
\sqrt{7} \cdot (-\sqrt{2}) = -\sqrt{7} \cdot \sqrt{2}
\]
By the property of square roots, \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \), we can combine the radicals:
\[
-\sqrt{7 \cdot 2} = -\sqrt{14}
\]
Thus, the product of \( \sqrt{7} \) and \( -\sqrt{2} \) is:
\[
-\sqrt{14}
\]
\[
\sqrt{7} \cdot (-\sqrt{2}) = -\sqrt{7} \cdot \sqrt{2}
\]
By the property of square roots, \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \), we can combine the radicals:
\[
-\sqrt{7 \cdot 2} = -\sqrt{14}
\]
Thus, the product of \( \sqrt{7} \) and \( -\sqrt{2} \) is:
\[
-\sqrt{14}
\]
There are no human answers yet. A form for humans to post answers is coming very soon!