Question

What is the density of a piece of wood that has a mass of 7 g and a volume of 10 cm3 (1 cm3 = 1 mL, so 10 cm3 = 10 mL)? What is the density of the wood when the piece of wood is cut in half?

(1 point)
Responses

0.7 g/cm3 and 0.35 g/cm3
0.7 g/cm3 and 0.35 g/cm3

0.7 g/cm3 and still 0.7g/cm3
0.7 g/cm3 and still 0.7g/cm3

0.7 g/cm3 and 1.4 g/cm3
0.7 g/cm3 and 1.4 g/cm3

70 g/cm3 and still 70 g/cm3

Answer 1

To find the density of the wood, we can use the formula for density, which is:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

Given that the mass of the piece of wood is 7 g and the volume is 10 cm³, we can calculate the density:

\[
\text{Density} = \frac{7 \text{ g}}{10 \text{ cm}^3} = 0.7 \text{ g/cm}^3
\]

When the piece of wood is cut in half, the mass and volume will both be halved:

- New mass = \( \frac{7 \text{ g}}{2} = 3.5 \text{ g} \)
- New volume = \( \frac{10 \text{ cm}^3}{2} = 5 \text{ cm}^3 \)

Now we calculate the density of one half of the wood:

\[
\text{Density} = \frac{3.5 \text{ g}}{5 \text{ cm}^3} = 0.7 \text{ g/cm}^3
\]

Thus, the density of the wood when it is cut in half remains the same.

The correct answer is:

**0.7 g/cm³ and still 0.7 g/cm³**.