To solve the equation \( x^2 = 9x + 10 \), we first rearrange it to set it to zero:
\[ x^2 - 9x - 10 = 0 \]
Now we can factor this quadratic equation. We are looking for two numbers that multiply to \(-10\) (the constant term) and add to \(-9\) (the coefficient of \(x\)).
The numbers that satisfy these conditions are \(-10\) and \(1\), since:
\[ -10 \times 1 = -10 \ -10 + 1 = -9 \]
Now we can rewrite and factor the quadratic:
\[ (x - 10)(x + 1) = 0 \]
Setting each factor to zero gives us the solutions:
- \(x - 10 = 0 \) → \( x = 10 \)
- \(x + 1 = 0 \) → \( x = -1 \)
Therefore, the solutions to the equation \( x^2 = 9x + 10 \) are:
\[ x = 10, -1 \]
So the answer is:
\[ 10, -1 \]