Question
1. Students are running an experiment in which they are measuring the acceleration after applying forces to a cart. Using the data above, what is the mass of the cart?
Trial: 1, 2, 3
Force (N): 10 N, 12, 22
Acceleration (m/s^2): 2.5, 3, 5.5
A) 2 kg
B) 4 kg
C) 6 kg
D) 8 kg
2. The table below shows the mass and velocity of four objects. Which object has the least inertia?
Object: W, X, Y, Z
Mass (kg): 16, 15, 13, 2
Velocity (m/s): 2, 3, 20, 30
A) Z
B) X
C) Y
D) W
3. Balance the following the chemical equation: _ Na2O + _ CaBr2 - _ NaBr + _ CaO
A) 1:1:1:2
B) 1:2:1:1
C) 1:1:2:1
D) 2:1:1:1
4. During an experiment in which you are investigating the acceleration changes due to force changes, what value must stay constant during these trials?
a
Force
b
Velocity
c
Acceleration
d
Mass
5. Which of the following phase changes involves a gas turning into a liquid?
A) Condensation
B) Boiling
C) Sublimation
D) Freezing
6. A block with a mass of 55 kg is pulled with a force of 220 N to the right. Assuming a frictionless surface, what will be the acceleration of the block?
A) 22 m/s2
B) 0.25 m/s2
C) 9.8 m/s2
D) 4.0 m/s2
Trial: 1, 2, 3
Force (N): 10 N, 12, 22
Acceleration (m/s^2): 2.5, 3, 5.5
A) 2 kg
B) 4 kg
C) 6 kg
D) 8 kg
2. The table below shows the mass and velocity of four objects. Which object has the least inertia?
Object: W, X, Y, Z
Mass (kg): 16, 15, 13, 2
Velocity (m/s): 2, 3, 20, 30
A) Z
B) X
C) Y
D) W
3. Balance the following the chemical equation: _ Na2O + _ CaBr2 - _ NaBr + _ CaO
A) 1:1:1:2
B) 1:2:1:1
C) 1:1:2:1
D) 2:1:1:1
4. During an experiment in which you are investigating the acceleration changes due to force changes, what value must stay constant during these trials?
a
Force
b
Velocity
c
Acceleration
d
Mass
5. Which of the following phase changes involves a gas turning into a liquid?
A) Condensation
B) Boiling
C) Sublimation
D) Freezing
6. A block with a mass of 55 kg is pulled with a force of 220 N to the right. Assuming a frictionless surface, what will be the acceleration of the block?
A) 22 m/s2
B) 0.25 m/s2
C) 9.8 m/s2
D) 4.0 m/s2
Answers
GPT-4o mini
Let's solve the questions one by one:
1. To find the mass of the cart, we can use Newton's second law, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
Using the data from the trials:
- For Trial 1:
- \( F = 10 \, \text{N} \)
- \( a = 2.5 \, \text{m/s}^2 \)
- Therefore, \( m = \frac{F}{a} = \frac{10}{2.5} = 4 \, \text{kg} \)
- For Trial 2:
- \( F = 12 \, \text{N} \)
- \( a = 3 \, \text{m/s}^2 \)
- Therefore, \( m = \frac{12}{3} = 4 \, \text{kg} \)
- For Trial 3:
- \( F = 22 \, \text{N} \)
- \( a = 5.5 \, \text{m/s}^2 \)
- Therefore, \( m = \frac{22}{5.5} = 4 \, \text{kg} \)
Since the mass is consistent across all trials, the mass of the cart is **4 kg** (Answer: B).
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2. Inertia is directly related to mass; the greater the mass, the greater the inertia. Among the objects:
- Object W: 16 kg
- Object X: 15 kg
- Object Y: 13 kg
- Object Z: 2 kg
Object Z has the least mass and therefore the least inertia. So the answer is **Z** (Answer: A).
---
3. To balance the chemical equation \( \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \), we can balance each element:
- Sodium (Na): 2 on the left, so we need 2 NaBr on the right.
- Calcium (Ca): 1 on both sides.
- Oxygen (O): 1 on the left, so we need 1 on the right.
- Bromine (Br): 2 on the left (from CaBr2), therefore, we need 2 on the right (from 2 NaBr).
So the balanced equation is \( 1 \text{Na}_2\text{O} + 1 \text{CaBr}_2 \rightarrow 2 \text{NaBr} + 1 \text{CaO} \).
Thus, the coefficients are 1:1:2:1 (Answer: C).
---
4. During the experiment, the correct constant value that must be maintained is **Mass**. The goal is to observe how acceleration changes due to varying force while keeping the mass constant (Answer: d).
---
5. The phase change that involves a gas turning into a liquid is called **Condensation** (Answer: A).
---
6. To find the acceleration of the block, we can again use Newton's second law \( F = m \cdot a \):
- Given:
- Mass \( m = 55 \, \text{kg} \)
- Force \( F = 220 \, \text{N} \)
Using the formula, we rearrange it to solve for acceleration:
\[ a = \frac{F}{m} = \frac{220 \, \text{N}}{55 \, \text{kg}} = 4 \, \text{m/s}^2 \]
Thus, the acceleration of the block is **4.0 m/s²** (Answer: D).
1. To find the mass of the cart, we can use Newton's second law, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
Using the data from the trials:
- For Trial 1:
- \( F = 10 \, \text{N} \)
- \( a = 2.5 \, \text{m/s}^2 \)
- Therefore, \( m = \frac{F}{a} = \frac{10}{2.5} = 4 \, \text{kg} \)
- For Trial 2:
- \( F = 12 \, \text{N} \)
- \( a = 3 \, \text{m/s}^2 \)
- Therefore, \( m = \frac{12}{3} = 4 \, \text{kg} \)
- For Trial 3:
- \( F = 22 \, \text{N} \)
- \( a = 5.5 \, \text{m/s}^2 \)
- Therefore, \( m = \frac{22}{5.5} = 4 \, \text{kg} \)
Since the mass is consistent across all trials, the mass of the cart is **4 kg** (Answer: B).
---
2. Inertia is directly related to mass; the greater the mass, the greater the inertia. Among the objects:
- Object W: 16 kg
- Object X: 15 kg
- Object Y: 13 kg
- Object Z: 2 kg
Object Z has the least mass and therefore the least inertia. So the answer is **Z** (Answer: A).
---
3. To balance the chemical equation \( \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \), we can balance each element:
- Sodium (Na): 2 on the left, so we need 2 NaBr on the right.
- Calcium (Ca): 1 on both sides.
- Oxygen (O): 1 on the left, so we need 1 on the right.
- Bromine (Br): 2 on the left (from CaBr2), therefore, we need 2 on the right (from 2 NaBr).
So the balanced equation is \( 1 \text{Na}_2\text{O} + 1 \text{CaBr}_2 \rightarrow 2 \text{NaBr} + 1 \text{CaO} \).
Thus, the coefficients are 1:1:2:1 (Answer: C).
---
4. During the experiment, the correct constant value that must be maintained is **Mass**. The goal is to observe how acceleration changes due to varying force while keeping the mass constant (Answer: d).
---
5. The phase change that involves a gas turning into a liquid is called **Condensation** (Answer: A).
---
6. To find the acceleration of the block, we can again use Newton's second law \( F = m \cdot a \):
- Given:
- Mass \( m = 55 \, \text{kg} \)
- Force \( F = 220 \, \text{N} \)
Using the formula, we rearrange it to solve for acceleration:
\[ a = \frac{F}{m} = \frac{220 \, \text{N}}{55 \, \text{kg}} = 4 \, \text{m/s}^2 \]
Thus, the acceleration of the block is **4.0 m/s²** (Answer: D).