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A carnival is arriving in the neighborhood.Leo has saved a $15 to spend at the carnival on food and attractions.Food items cost...Question
The carnival is arriving in the neighborhood! Leo has saved up $15 to spend at the carnival on food and attractions. Food items cost $4 each and attractions cost $2 each. Leo uses the expression 4a + 2b to determine the total cost for a food items and b attractions.
Select one of the following combinations of food items and attractions that Leo can afford with his $15 budget:
(1 point)
Responses
1 food item and 5 attractions
1 food item and 5 attractions
3 food items and 2 attractions
3 food items and 2 attractions
2 food items and 4 attractions
2 food items and 4 attractions
0 food items and 8 attractions
Select one of the following combinations of food items and attractions that Leo can afford with his $15 budget:
(1 point)
Responses
1 food item and 5 attractions
1 food item and 5 attractions
3 food items and 2 attractions
3 food items and 2 attractions
2 food items and 4 attractions
2 food items and 4 attractions
0 food items and 8 attractions
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which combination of food items and attractions Leo can afford with his $15 budget, we can plug in each option into the expression \(4a + 2b\) (where \(a\) is the number of food items and \(b\) is the number of attractions) and check if the total cost is less than or equal to $15.
1. **1 food item and 5 attractions:**
\[
4(1) + 2(5) = 4 + 10 = 14
\]
(Leo can afford this.)
2. **3 food items and 2 attractions:**
\[
4(3) + 2(2) = 12 + 4 = 16
\]
(Leo cannot afford this.)
3. **2 food items and 4 attractions:**
\[
4(2) + 2(4) = 8 + 8 = 16
\]
(Leo cannot afford this.)
4. **0 food items and 8 attractions:**
\[
4(0) + 2(8) = 0 + 16 = 16
\]
(Leo cannot afford this.)
The only combination that Leo can afford is **1 food item and 5 attractions**.
1. **1 food item and 5 attractions:**
\[
4(1) + 2(5) = 4 + 10 = 14
\]
(Leo can afford this.)
2. **3 food items and 2 attractions:**
\[
4(3) + 2(2) = 12 + 4 = 16
\]
(Leo cannot afford this.)
3. **2 food items and 4 attractions:**
\[
4(2) + 2(4) = 8 + 8 = 16
\]
(Leo cannot afford this.)
4. **0 food items and 8 attractions:**
\[
4(0) + 2(8) = 0 + 16 = 16
\]
(Leo cannot afford this.)
The only combination that Leo can afford is **1 food item and 5 attractions**.
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