Question
Which equation has infinitely many solutions?
1-2x=2(1-x)
1-2x=2(1-x)
Answers
Answered by
GPT-4o mini
To determine if the equation \( 1 - 2x = 2(1 - x) \) has infinitely many solutions, let's simplify the equation.
Start by expanding the right side:
\[
1 - 2x = 2 - 2x
\]
Next, rearrange both sides:
1. Subtract \( 2 \) from both sides:
\[
1 - 2 = 2 - 2x - 2x
\]
\[
-1 = 2 - 2x
\]
2. Now, subtract \( 1 \) from both sides:
\[
0 = 2 - 2x + 1
\]
This simplifies to:
\[
0 = 2 - 2x - 1
\]
Now combine like terms:
\[
0 = 1 - 2x
\]
3. Rearranging gives:
\[
2x = 1
\]
4. Divide by 2:
\[
x = \frac{1}{2}
\]
Since we have found a specific solution, \( x = \frac{1}{2} \), this equation only has one solution, not infinitely many.
Therefore, the equation \( 1 - 2x = 2(1 - x) \) does **not** have infinitely many solutions. It has exactly one solution:
\[
x = \frac{1}{2}
\]
Start by expanding the right side:
\[
1 - 2x = 2 - 2x
\]
Next, rearrange both sides:
1. Subtract \( 2 \) from both sides:
\[
1 - 2 = 2 - 2x - 2x
\]
\[
-1 = 2 - 2x
\]
2. Now, subtract \( 1 \) from both sides:
\[
0 = 2 - 2x + 1
\]
This simplifies to:
\[
0 = 2 - 2x - 1
\]
Now combine like terms:
\[
0 = 1 - 2x
\]
3. Rearranging gives:
\[
2x = 1
\]
4. Divide by 2:
\[
x = \frac{1}{2}
\]
Since we have found a specific solution, \( x = \frac{1}{2} \), this equation only has one solution, not infinitely many.
Therefore, the equation \( 1 - 2x = 2(1 - x) \) does **not** have infinitely many solutions. It has exactly one solution:
\[
x = \frac{1}{2}
\]
There are no human answers yet. A form for humans to post answers is coming very soon!