Question

Imagine a scenario in which an animal's force is pushing itself forward 5 N, friction is pushing it 4 N backward, gravity is pushing the animal 10 N down, and the animal is pushing itself 10 N up. Describe the movement of the animal.(1 point)
Responses

It moves 10 N down and 10 N up as those are the greatest forces acting on the animal.
It moves 10 N down and 10 N up as those are the greatest forces acting on the animal.

It only moves forward because there is a net force forward.
It only moves forward because there is a net force forward.

It moves 29 N forward because that's the net force.
It moves 29 N forward because that's the net force.

It moves forward and upward because those are the greatest net forces.

Answer 1

To analyze the movement of the animal, we need to calculate the net forces acting in each direction:

1. **Horizontal Forces**:
- Forward force: 5 N
- Backward (friction) force: 4 N
- Net horizontal force = 5 N (forward) - 4 N (backward) = 1 N (forward)

2. **Vertical Forces**:
- Upward force: 10 N
- Downward force (gravity): 10 N
- Net vertical force = 10 N (up) - 10 N (down) = 0 N

Now, we can interpret these results:
- The net force acting on the animal in the horizontal direction is 1 N forward, which means it will move forward.
- The net force in the vertical direction is 0 N, meaning there is no movement up or down; the forces in the vertical direction are balanced.

Given this analysis, the correct response would be:

**It only moves forward because there is a net force forward.**