A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75−16t2 , where t is time in seconds.(1 point)

Answer 1

To find the height of the diver above the ocean after 2 seconds using the formula $h(t)=75-16t^2$, we need to substitute $t=2$ into the equation.

Given:

$$h(t)=75-16t^2$$

Substituting $t=2$:

$$h(2)=75-16(2^2)$$

Calculating $2^2$:

$$2^2=4$$

Now substituting back into the equation:

$$h(2)=75-16(4)$$

Calculating $16\times 4$:

$$16\times 4=64$$

Now substituting this value back:

$$h(2)=75-64$$

Finally, performing the subtraction:

$$h(2)=11$$

Therefore, the diver is 11 feet above the ocean after 2 seconds.