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Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessa...Asked by Kostragula
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary. (1 point) Responses 5.57 5.57 6:40 6:40 9 9 41
Answers
Answered by
Kostragula
4,2.
-1, -2
-1, -2
Answered by
GPT-4o mini
To find the length between two points using the Pythagorean theorem, we use the formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
where \( (x_1, y_1) \) and \( (x_2, y_2) \) are the coordinates of the two points.
If you provide the coordinates of the two points, I can compute the length for you.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
where \( (x_1, y_1) \) and \( (x_2, y_2) \) are the coordinates of the two points.
If you provide the coordinates of the two points, I can compute the length for you.
Answered by
GPT-4o mini
To find the distance between the points \( (4, 2) \) and \( (-1, -2) \), we can apply the Pythagorean Theorem as follows:
1. Identify the coordinates:
- \( (x_1, y_1) = (4, 2) \)
- \( (x_2, y_2) = (-1, -2) \)
2. Substitute the values into the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
3. Plug in the values:
\[
d = \sqrt{((-1) - 4)^2 + ((-2) - 2)^2}
\]
4. Calculate the differences:
\[
d = \sqrt{(-5)^2 + (-4)^2}
\]
5. Square the differences:
\[
d = \sqrt{25 + 16}
\]
6. Add the squares:
\[
d = \sqrt{41}
\]
7. Finally, calculate the square root:
\[
d \approx 6.4
\]
When rounded to the nearest hundredth, the distance \( d \) is approximately **6.40**.
1. Identify the coordinates:
- \( (x_1, y_1) = (4, 2) \)
- \( (x_2, y_2) = (-1, -2) \)
2. Substitute the values into the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
3. Plug in the values:
\[
d = \sqrt{((-1) - 4)^2 + ((-2) - 2)^2}
\]
4. Calculate the differences:
\[
d = \sqrt{(-5)^2 + (-4)^2}
\]
5. Square the differences:
\[
d = \sqrt{25 + 16}
\]
6. Add the squares:
\[
d = \sqrt{41}
\]
7. Finally, calculate the square root:
\[
d \approx 6.4
\]
When rounded to the nearest hundredth, the distance \( d \) is approximately **6.40**.
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