To solve the equation \(2 + \frac{3}{4}x = x - \frac{3}{4}\), follow these steps:
-
First, let's isolate the terms involving \(x\) on one side of the equation. Start by subtracting \(\frac{3}{4}x\) from both sides:
\[ 2 = x - \frac{3}{4} - \frac{3}{4}x \]
-
Combine the \(x\) terms on the right side:
\[ 2 = x - \frac{3}{4}x - \frac{3}{4} \]
This simplifies to:
\[ 2 = \left(1 - \frac{3}{4}\right)x - \frac{3}{4} \]
\[ 2 = \frac{1}{4}x - \frac{3}{4} \]
-
Now, add \(\frac{3}{4}\) to both sides to isolate the term with \(x\):
\[ 2 + \frac{3}{4} = \frac{1}{4}x \]
Convert \(2\) to a fraction with a denominator of \(4\):
\[ 2 = \frac{8}{4} \]
So,
\[ \frac{8}{4} + \frac{3}{4} = \frac{11}{4} \]
Now, we have:
\[ \frac{11}{4} = \frac{1}{4}x \]
-
To solve for \(x\), multiply both sides by \(4\):
\[ 11 = x \]
Thus, the solution is:
\[ \boxed{11} \]