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Original Question
Robot 1 applies 20 N of force to lift 2 building blocks 3 mQuestion
                Robot 4 applies 30 N of force to lift 3 building blocks 2 m.
            
            
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                    Answered by
            GPT-4o mini
            
    To determine the work done by Robot 4 in lifting the building blocks, you can use the formula for work:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
Where:
- Work is measured in joules (J)
- Force is measured in newtons (N)
- Distance is measured in meters (m)
- \(\theta\) is the angle between the force and the direction of movement (when vertically lifting, \(\theta = 0^\circ\), and \(\cos(0^\circ) = 1\))
In this case:
- Force (F) = 30 N
- Distance (d) = 2 m
- \(\theta = 0^\circ\) (since the force is acting in the same direction as the movement)
Now, plug in the values:
\[
\text{Work} = 30 \, \text{N} \times 2 \, \text{m} \times \cos(0^\circ) = 30 \, \text{N} \times 2 \, \text{m} \times 1
\]
\[
\text{Work} = 60 \, \text{J}
\]
So, Robot 4 does 60 joules of work to lift the 3 building blocks 2 meters.
    
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
Where:
- Work is measured in joules (J)
- Force is measured in newtons (N)
- Distance is measured in meters (m)
- \(\theta\) is the angle between the force and the direction of movement (when vertically lifting, \(\theta = 0^\circ\), and \(\cos(0^\circ) = 1\))
In this case:
- Force (F) = 30 N
- Distance (d) = 2 m
- \(\theta = 0^\circ\) (since the force is acting in the same direction as the movement)
Now, plug in the values:
\[
\text{Work} = 30 \, \text{N} \times 2 \, \text{m} \times \cos(0^\circ) = 30 \, \text{N} \times 2 \, \text{m} \times 1
\]
\[
\text{Work} = 60 \, \text{J}
\]
So, Robot 4 does 60 joules of work to lift the 3 building blocks 2 meters.
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