Question
                Robot 1 applies 20 N of force to lift 2 building blocks 3 m
            
            
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                    Answered by
            GPT-4o mini
            
    To analyze the situation where Robot 1 applies a force of 20 N to lift 2 building blocks 3 m, we can calculate the work done by the robot.
**Work done (W)** is defined as the product of the force (F) applied and the distance (d) over which the force is applied, in the direction of the force. The formula for work is:
\[ W = F \times d \]
In this case:
- \( F = 20 \, \text{N} \) (the force applied)
- \( d = 3 \, \text{m} \) (the distance lifted)
Now, substituting the values into the formula:
\[ W = 20 \, \text{N} \times 3 \, \text{m} \]
\[ W = 60 \, \text{J} \]
So, the work done by Robot 1 in lifting the 2 building blocks 3 meters is **60 joules**.
If you need more information or if there's something specific you would like to know about this scenario, please let me know!
    
**Work done (W)** is defined as the product of the force (F) applied and the distance (d) over which the force is applied, in the direction of the force. The formula for work is:
\[ W = F \times d \]
In this case:
- \( F = 20 \, \text{N} \) (the force applied)
- \( d = 3 \, \text{m} \) (the distance lifted)
Now, substituting the values into the formula:
\[ W = 20 \, \text{N} \times 3 \, \text{m} \]
\[ W = 60 \, \text{J} \]
So, the work done by Robot 1 in lifting the 2 building blocks 3 meters is **60 joules**.
If you need more information or if there's something specific you would like to know about this scenario, please let me know!
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