To create a true equivalent system for System A and System B, we can modify the equations while maintaining their solutions.
Let's start with the given equation from System A:
- \(-x + y = 1\)
We can manipulate this equation:
- Multiply the entire equation by \(-1\): \[x - y = -1\]
Now let's look at the options provided:
- \(2y = 12\) (this simplifies to \(y = 6\))
- \(-x - y = -1\) (this is equivalent to \(x + y = 1\))
- \(-2x - 2y = -22\) (this simplifies to \(2x + 2y = 22\))
- \(2x + 2y = 12\) (this simplifies to \(x + y = 6\))
None of these options directly provide an equivalent form of \(-x + y = 1\). However, let’s analyze option 3, which is \(-2x - 2y = -22\).
If we divide this equation by -2, we get:
\[ x + y = 11 \]
This is indeed equivalent to the given equation from System B.
So the correct answer is:
−2x−2y=−22 (negative 2 x minus 2 y equals negative 22)