Asked by QUAAACK
Solve for f.
f–4<20
f–4<20
Answers
Answered by
GPT-4o mini
To solve the inequality \( f - 4 < 20 \), you can isolate \( f \) by adding 4 to both sides:
\[
f - 4 + 4 < 20 + 4
\]
This simplifies to:
\[
f < 24
\]
Thus, the solution to the inequality is:
\[
f < 24
\]
\[
f - 4 + 4 < 20 + 4
\]
This simplifies to:
\[
f < 24
\]
Thus, the solution to the inequality is:
\[
f < 24
\]
Answered by
GPT-4o mini
To solve the inequality \( 4u \leq 72 \), you can isolate \( u \) by dividing both sides by 4:
\[
\frac{4u}{4} \leq \frac{72}{4}
\]
This simplifies to:
\[
u \leq 18
\]
Thus, the solution is:
\[
u \leq 18
\]
\[
\frac{4u}{4} \leq \frac{72}{4}
\]
This simplifies to:
\[
u \leq 18
\]
Thus, the solution is:
\[
u \leq 18
\]
Answered by
GPT-4o mini
To find an equivalent fraction to \( \frac{2}{6} \), you can simplify it by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 2.
\[
\frac{2 \div 2}{6 \div 2} = \frac{1}{3}
\]
So, \( \frac{1}{3} \) is an equivalent fraction to \( \frac{2}{6} \).
Additionally, you can also create equivalent fractions by multiplying both the numerator and the denominator by the same number. For example:
- Multiplying by 2:
\[
\frac{2 \times 2}{6 \times 2} = \frac{4}{12}
\]
- Multiplying by 3:
\[
\frac{2 \times 3}{6 \times 3} = \frac{6}{18}
\]
So, other equivalent fractions to \( \frac{2}{6} \) include \( \frac{4}{12} \) and \( \frac{6}{18} \).
\[
\frac{2 \div 2}{6 \div 2} = \frac{1}{3}
\]
So, \( \frac{1}{3} \) is an equivalent fraction to \( \frac{2}{6} \).
Additionally, you can also create equivalent fractions by multiplying both the numerator and the denominator by the same number. For example:
- Multiplying by 2:
\[
\frac{2 \times 2}{6 \times 2} = \frac{4}{12}
\]
- Multiplying by 3:
\[
\frac{2 \times 3}{6 \times 3} = \frac{6}{18}
\]
So, other equivalent fractions to \( \frac{2}{6} \) include \( \frac{4}{12} \) and \( \frac{6}{18} \).
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