Question
An electron, moving with a speed, 6.8 km/s, enters a magnetic field that has a strength of 6.9 T. The magnetic force on the electron is perpendicular to the electron's velocity. Determine the radius of the resultant path of the electron.
Answers
bobpursley
centripetal force=magnetic force
mv^2/r=Bqv
solve for r.
mv^2/r=Bqv
solve for r.
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