Asked by Jamie
An electron, moving with a speed, 6.8 km/s, enters a magnetic field that has a strength of 6.9 T. The magnetic force on the electron is perpendicular to the electron's velocity. Determine the radius of the resultant path of the electron.
Answers
Answered by
bobpursley
centripetal force=magnetic force
mv^2/r=Bqv
solve for r.
mv^2/r=Bqv
solve for r.
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