To compare the kinetic energy of Watermelon A and Watermelon B, we can use the formula for kinetic energy (KE):
\[ \text{KE} = \frac{1}{2} m v^2 \]
where \( m \) is the mass and \( v \) is the speed.
For Watermelon A:
- Mass = 4 kg
- Speed = 2 m/s
\[ \text{KE}_A = \frac{1}{2} \times 4 \times (2^2) = \frac{1}{2} \times 4 \times 4 = 8 , \text{J} \]
For Watermelon B:
- Mass = 4 kg
- Speed = 4 m/s
\[ \text{KE}_B = \frac{1}{2} \times 4 \times (4^2) = \frac{1}{2} \times 4 \times 16 = 32 , \text{J} \]
Now comparing the kinetic energies:
- KE of Watermelon A = 8 J
- KE of Watermelon B = 32 J
Therefore, Watermelon B has more kinetic energy.
Regarding potential energy, since both watermelons start at the same height on the kitchen counter and have the same mass, their potential energy will also be the same before they fall.
Based on the calculations:
Response: The watermelon B has more kinetic energy.
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