Question

Which ordered pair is in the solution set of 8x + 16y > 32?




A.
(4, 0)


B.
(−3, 5)


C.
(−1, 1)


D.
(0, 2)

Answer 1

To determine which ordered pair is in the solution set of the inequality \( 8x + 16y > 32 \), we can substitute each pair into the inequality and check if it holds true.

Let's evaluate each option:

A. \( (4, 0) \):
\[
8(4) + 16(0) = 32 \quad \text{(not greater)}
\]

B. \( (-3, 5) \):
\[
8(-3) + 16(5) = -24 + 80 = 56 \quad \text{(greater than 32)}
\]

C. \( (-1, 1) \):
\[
8(-1) + 16(1) = -8 + 16 = 8 \quad \text{(not greater)}
\]

D. \( (0, 2) \):
\[
8(0) + 16(2) = 0 + 32 = 32 \quad \text{(not greater)}
\]

The only ordered pair that satisfies the inequality \( 8x + 16y > 32 \) is:

**B. \( (-3, 5) \)**