To determine the probability of landing on a 5 on the first spin and then landing on a number greater than 4 on the second spin, we need to know the structure of the spinner. However, a common example is a spinner with the numbers 1 through 6, like a standard die.
Assuming this is the case, we can calculate the probabilities as follows:
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Probability of landing on a 5 on the first spin:
- There is 1 favorable outcome (landing on a 5) out of 6 possible outcomes (1, 2, 3, 4, 5, 6).
- Therefore, the probability of landing on a 5 is \( P(5) = \frac{1}{6} \).
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Probability of landing on a number greater than 4 on the second spin:
- The numbers greater than 4 on a standard spinner (1 to 6) are 5 and 6. There are 2 favorable outcomes (5, 6) out of 6 possible outcomes.
- Thus, the probability of landing on a number greater than 4 is \( P(\text{greater than 4}) = \frac{2}{6} = \frac{1}{3} \).
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Combined probability:
- Since the spins are independent events, the combined probability of both events occurring (landing on a 5 first, then landing on a number greater than 4) is the product of their individual probabilities: \[ P(5 \text{ and then } >4) = P(5) \times P(>4) = \frac{1}{6} \times \frac{1}{3} = \frac{1}{18}. \]
Thus, the probability of landing on a 5 on the first spin and then landing on a number greater than 4 on the second spin is \( \frac{1}{18} \).