Question

A person exerts a force of 1.5 Newtons to push an object a distance of 2 meters. How much work is done on the object?

Answer 1

Work is calculated using the formula:

\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]

where:
- \(\text{Work}\) is measured in Joules (J),
- \(\text{Force}\) is measured in Newtons (N),
- \(\text{Distance}\) is measured in meters (m),
- \(\theta\) is the angle between the force and the direction of motion.

If the force is applied in the same direction as the motion of the object, then \(\theta = 0^\circ\) and \(\cos(0) = 1\).

In this case:
- Force \(F = 1.5 \, \text{N}\)
- Distance \(d = 2 \, \text{m}\)
- \(\theta = 0^\circ \implies \cos(0) = 1\)

Now, substituting the values into the work formula:

\[
\text{Work} = 1.5 \, \text{N} \times 2 \, \text{m} \times 1
\]

\[
\text{Work} = 3 \, \text{J}
\]

Thus, the work done on the object is \(3\) Joules.