To find the length of the other leg in a right triangle, we can use the Pythagorean theorem, which states that:
\[ a^2 + b^2 = c^2 \]
where \(a\) and \(b\) are the legs of the triangle and \(c\) is the hypotenuse.
In this problem, we have one leg \(a = 12\) and the hypotenuse \(c = 16\). We need to find the length of the other leg \(b\).
Substituting the known values into the Pythagorean theorem:
\[ 12^2 + b^2 = 16^2 \]
Calculating the squares:
\[ 144 + b^2 = 256 \]
Next, we isolate \(b^2\):
\[ b^2 = 256 - 144 \] \[ b^2 = 112 \]
Now, we take the square root of both sides to find \(b\):
\[ b = \sqrt{112} \]
To simplify \(\sqrt{112}\):
\[ \sqrt{112} = \sqrt{16 \cdot 7} = \sqrt{16} \cdot \sqrt{7} = 4\sqrt{7} \]
Calculating \(4\sqrt{7}\):
Using the approximate value \(\sqrt{7} \approx 2.64575\),
\[ 4\sqrt{7} \approx 4 \cdot 2.64575 \approx 10.583 \]
Rounding it to the nearest tenth:
\[ b \approx 10.6 \]
So, the length of the other leg is:
\[ \boxed{10.6} \]