Question
If R. is the midpoint of segment AM, find midpoint R.
(1 point)
R is located at (-2,-2).
R is located at (-2,2.5).
R is located at (0, 2.5).
R is located at (-2,7).
A: (-2,4)
M: (-2,1)
(1 point)
R is located at (-2,-2).
R is located at (-2,2.5).
R is located at (0, 2.5).
R is located at (-2,7).
A: (-2,4)
M: (-2,1)
Answers
GPT-4o mini
To find the midpoint \( R \) of segment \( AM \), we can use the midpoint formula, which is given by:
\[
R\left(x, y\right) = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)
\]
where \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( M \).
In this case, we have:
- \( A: (-2, 4) \)
- \( M: (-2, 1) \)
Now, let's substitute the coordinates into the midpoint formula:
\[
R\left(x, y\right) = \left(\frac{-2 + (-2)}{2}, \frac{4 + 1}{2}\right)
\]
Calculating the \( x \)-coordinate:
\[
\frac{-2 - 2}{2} = \frac{-4}{2} = -2
\]
Calculating the \( y \)-coordinate:
\[
\frac{4 + 1}{2} = \frac{5}{2} = 2.5
\]
So the coordinates for midpoint \( R \) are:
\[
R = (-2, 2.5)
\]
Therefore, the correct answer is:
**R is located at (-2, 2.5).**
\[
R\left(x, y\right) = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)
\]
where \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( M \).
In this case, we have:
- \( A: (-2, 4) \)
- \( M: (-2, 1) \)
Now, let's substitute the coordinates into the midpoint formula:
\[
R\left(x, y\right) = \left(\frac{-2 + (-2)}{2}, \frac{4 + 1}{2}\right)
\]
Calculating the \( x \)-coordinate:
\[
\frac{-2 - 2}{2} = \frac{-4}{2} = -2
\]
Calculating the \( y \)-coordinate:
\[
\frac{4 + 1}{2} = \frac{5}{2} = 2.5
\]
So the coordinates for midpoint \( R \) are:
\[
R = (-2, 2.5)
\]
Therefore, the correct answer is:
**R is located at (-2, 2.5).**