A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2

by using the formula 75−16t2
, where t
is time in seconds.(1 point)

1 answer

To find the height of the diver above the ocean after 2 seconds, we can use the provided formula:

\[ h(t) = 75 - 16t^2 \]

where \( h(t) \) is the height in feet and \( t \) is the time in seconds. We need to evaluate this function at \( t = 2 \):

\[ h(2) = 75 - 16(2^2) \]

First, calculate \( 2^2 \):

\[ 2^2 = 4 \]

Now substitute that back into the equation:

\[ h(2) = 75 - 16(4) \]

Next, calculate \( 16 \times 4 \):

\[ 16 \times 4 = 64 \]

Now substitute that value into the equation:

\[ h(2) = 75 - 64 \]

Finally, perform the subtraction:

\[ h(2) = 11 \]

Thus, the diver is 11 feet above the ocean after 2 seconds.