To find the height of the diver above the ocean after 2 seconds, we can use the provided formula:
\[ h(t) = 75 - 16t^2 \]
where \( h(t) \) is the height in feet and \( t \) is the time in seconds. We need to evaluate this function at \( t = 2 \):
\[ h(2) = 75 - 16(2^2) \]
First, calculate \( 2^2 \):
\[ 2^2 = 4 \]
Now substitute that back into the equation:
\[ h(2) = 75 - 16(4) \]
Next, calculate \( 16 \times 4 \):
\[ 16 \times 4 = 64 \]
Now substitute that value into the equation:
\[ h(2) = 75 - 64 \]
Finally, perform the subtraction:
\[ h(2) = 11 \]
Thus, the diver is 11 feet above the ocean after 2 seconds.