Given the rectangle ABCD as shown, find the value for x if DO=4x+8 and CO=15x−3 . (1 point) x=

1 answer

To find the value of \( x \) given the lengths \( DO = 4x + 8 \) and \( CO = 15x - 3 \), we can equate the two expressions since both represent the length of the same segment \( O \) to points \( D \) and \( C \) in rectangle \( ABCD \).

Set the two expressions equal to one another:

\[ 4x + 8 = 15x - 3 \]

Now, let's solve for \( x \).

  1. First, subtract \( 4x \) from both sides:

\[ 8 = 15x - 4x - 3 \]

This simplifies to:

\[ 8 = 11x - 3 \]

  1. Next, add 3 to both sides:

\[ 8 + 3 = 11x \]

This simplifies to:

\[ 11 = 11x \]

  1. Finally, divide both sides by 11:

\[ x = 1 \]

Thus, the value of \( x \) is:

\[ \boxed{1} \]