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What is the greatest common factor of 72,96 and 128Asked by ψ(`∇´)ψ
What is the greatest common factor of 72, 60, and 56?
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Answered by
GPT-4o mini
To find the greatest common factor (GCF) of the numbers 72, 60, and 56, we can start by finding the prime factorization of each number.
1. **Factorization of 72**:
\[
72 = 2^3 \times 3^2
\]
2. **Factorization of 60**:
\[
60 = 2^2 \times 3^1 \times 5^1
\]
3. **Factorization of 56**:
\[
56 = 2^3 \times 7^1
\]
Next, we identify the common prime factors from the factorizations of these numbers:
- The only prime factor common to all three numbers is \(2\).
Now, we determine the lowest power of the common prime factor:
- For \(2\):
- In 72, the power is \(3\) (i.e., \(2^3\)).
- In 60, the power is \(2\) (i.e., \(2^2\)).
- In 56, the power is \(3\) (i.e., \(2^3\)).
The minimum power of \(2\) present in all factorizations is \(2^2\).
Thus, the GCF can be calculated as:
\[
GCF = 2^2 = 4
\]
Therefore, the greatest common factor of 72, 60, and 56 is \(\boxed{4}\).
1. **Factorization of 72**:
\[
72 = 2^3 \times 3^2
\]
2. **Factorization of 60**:
\[
60 = 2^2 \times 3^1 \times 5^1
\]
3. **Factorization of 56**:
\[
56 = 2^3 \times 7^1
\]
Next, we identify the common prime factors from the factorizations of these numbers:
- The only prime factor common to all three numbers is \(2\).
Now, we determine the lowest power of the common prime factor:
- For \(2\):
- In 72, the power is \(3\) (i.e., \(2^3\)).
- In 60, the power is \(2\) (i.e., \(2^2\)).
- In 56, the power is \(3\) (i.e., \(2^3\)).
The minimum power of \(2\) present in all factorizations is \(2^2\).
Thus, the GCF can be calculated as:
\[
GCF = 2^2 = 4
\]
Therefore, the greatest common factor of 72, 60, and 56 is \(\boxed{4}\).
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