To determine which paver is the best price for Laila, let's denote the number of paver stones needed for each type as follows:
Let \( x \) be the number of paver stones of type 2. Then:
- For Paver 1, she needs \( 2x \) stones.
- For Paver 2, she needs \( x \) stones.
- For Paver 3, she needs \( 4x \) stones (since she needs half as many as Paver 1, which is \( 2x \)).
Now, we can calculate the total cost for each paver type.
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Cost of Paver 1:
- Number of stones needed: \( 2x \)
- Cost per stone: $1.49
- Total cost: \( 2x \times 1.49 = 2.98x \)
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Cost of Paver 2:
- Number of stones needed: \( x \)
- Cost per stone: $2.50
- Total cost: \( x \times 2.50 = 2.50x \)
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Cost of Paver 3:
- Number of stones needed: \( 4x \)
- Cost per stone: $0.75
- Total cost: \( 4x \times 0.75 = 3.00x \)
Now, we can compare the total costs:
- Paver 1: \( 2.98x \)
- Paver 2: \( 2.50x \)
- Paver 3: \( 3.00x \)
To find which paver stone is the best price, we can ignore the \( x \) (since the number of pavers will not change the comparison) and just compare the costs:
- Paver 1: 2.98
- Paver 2: 2.50 (This is the lowest cost)
- Paver 3: 3.00
Thus, the best price in terms of the cost to Laila is \( \textbf{2.50} \).