Expand 6(x+1)

11 answers

To expand 6(x+1), you distribute the 6 to both terms inside the parentheses:

6(x+1)=6x+61

This simplifies to:

6x+6

So, the expanded form of 6(x+1) is 6x+6.

So what’s the answer

The expanded form of 6(x+1) is 6x+6.

Expand 4(3z−7)

To expand 4(3z7), you distribute the 4 to both terms inside the parentheses:

4(3z7)=43z+4(7)

This simplifies to:

12z28

So, the expanded form of 4(3z7) is 12z28.

Expand −5(2q+8)

To expand 5(2q+8), you distribute the 5 to both terms inside the parentheses:

5(2q+8)=52q+(5)8

This simplifies to:

10q40

So, the expanded form of 5(2q+8) is 10q40.

Expand 710(5d+6) .

To expand 710(5d+6), you distribute 710 to both terms inside the parentheses:

710(5d+6)=7105d+7106

This simplifies to:

3550d+4260

So, the expanded form of 710(5d+6) is 3550d+4260.

Expand 7/10(5d+6).(1 point)
Responses

35d + 6
35d + 6

5d + 21/5
5 d + 21 fifths

35d + 42
35d + 42

7/2d + 21/5

To expand 710(5d+6), you distribute 710 to both terms inside the parentheses:

710(5d)+710(6)

Calculating each term:

  1. 7105d=3510d=3.5d or 72d when simplified.
  2. 7106=4210=215 when simplified.

So, the expanded form is:

72d+215

Thus, the correct response from your options is:

72d+215.

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