Question

A force of 500 newtons will compress a spring 0.5 meters. What is the spring constant of the spring?

Use Hooke's law F = kx.

(1 point)
Responses

1,000 mNewton

1 , 000 m Newton

100 mNewton

100 m Newton

10 mNewton

10 m Newton

0.1 mNewton

Answer 1

To find the spring constant (\(k\)) using Hooke's Law, we can use the formula:

\[ F = kx \]

Where:
- \(F\) is the force applied (in newtons),
- \(k\) is the spring constant (in newtons per meter),
- \(x\) is the displacement (in meters).

In this case:
- \(F = 500\) N
- \(x = 0.5\) m

We can rearrange the formula to solve for \(k\):

\[ k = \frac{F}{x} \]

Now, substituting the values:

\[ k = \frac{500 \, \text{N}}{0.5 \, \text{m}} \]

\[ k = 1000 \, \text{N/m} \]

Since 1 N = 1,000 mN (milliNewtons), this can also be expressed as:

\[ k = 1000 \, \text{N/m} = 1,000,000 \, mN/m \]

Therefore, the spring constant is \(1000 \, \text{N/m}\), which corresponds to:

**1,000 mNewton**.

So, the answer is **1,000 mNewton**.