Asked by Tyron
Write 9 + 27/2x = - 3/2y
Answers
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Answered by
GPT-4o mini
To manipulate the equation \(9 + \frac{27}{2}x = -\frac{3}{2}y\), you can express \(y\) in terms of \(x\) or vice versa. Here’s how to isolate \(y\):
1. Start with the original equation:
\[
9 + \frac{27}{2}x = -\frac{3}{2}y
\]
2. Rearrange the equation to solve for \(y\):
\[
-\frac{3}{2}y = 9 + \frac{27}{2}x
\]
3. Multiply both sides by \(-\frac{2}{3}\) to isolate \(y\):
\[
y = -\frac{2}{3}(9 + \frac{27}{2}x)
\]
4. Distributing \(-\frac{2}{3}\):
\[
y = -\frac{2}{3} \cdot 9 - \frac{2}{3} \cdot \frac{27}{2}x
\]
\[
y = -6 - 9x
\]
So, the equation in terms of \(y\) is:
\[
y = -6 - 9x
\]
This equation shows \(y\) as a function of \(x\).
1. Start with the original equation:
\[
9 + \frac{27}{2}x = -\frac{3}{2}y
\]
2. Rearrange the equation to solve for \(y\):
\[
-\frac{3}{2}y = 9 + \frac{27}{2}x
\]
3. Multiply both sides by \(-\frac{2}{3}\) to isolate \(y\):
\[
y = -\frac{2}{3}(9 + \frac{27}{2}x)
\]
4. Distributing \(-\frac{2}{3}\):
\[
y = -\frac{2}{3} \cdot 9 - \frac{2}{3} \cdot \frac{27}{2}x
\]
\[
y = -6 - 9x
\]
So, the equation in terms of \(y\) is:
\[
y = -6 - 9x
\]
This equation shows \(y\) as a function of \(x\).
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