Question

(0, -2)Use the graph of the exponential decay function that models an exponential decay sequence to discuss the properties and determine the equation for the horizontal asymptote of the graph.

Answers

Answer
the equation for the graph is y=5(.3)^x -7
Answered by GPT-4o mini
To discuss the properties and determine the equation for the horizontal asymptote of an exponential decay function, let's go through the characteristics of such a function.

1. **General Form**: The general form of an exponential decay function can be expressed as:
\[
y = a \cdot b^{x}
\]
where:
- \(a\) is the initial value (when \(x=0\)),
- \(b\) (the base) is a positive number between 0 and 1 (for decay).

2. **Characteristics**:
- The function decreases rapidly at first and then levels off.
- As \(x\) increases, \(y\) approaches 0 but never actually reaches it.
- The graph is continuous and smooth.

3. **Horizontal Asymptote**: The horizontal asymptote of an exponential decay function represents a value that the function approaches as \(x\) approaches positive infinity. For all exponential decay functions, the horizontal asymptote is at:
\[
y = 0
\]
This means that the function will never actually touch or cross the line \(y = 0\).

4. **Example with Specific Point (0, -2)**:
If you have the point (0, -2), this suggests the function has been translated or altered. The value at \(x = 0\) is -2 instead of the expected initial value from the standard form. This implies that the function can be adjusted to:
\[
y = a \cdot b^{x} - 2
\]
where \(a\) is the initial value that gives -2 when \(x = 0\) (i.e., setting \(a \cdot b^0 - 2 = -2\), which means \(a - 2 = -2\) therefore \(a = 0\)). So the function could look something like:
\[
y = 0 \cdot b^{x} - 2
\]

5. **Conclusion**: Regardless of the transformations applied, the horizontal asymptote remains at:
\[
y = -2
\]
This means that as \(x\) increases, the function will approach the line \(y = -2\).

In summary, the properties of the exponential decay function suggest it decreases but approaches a horizontal asymptote of \(y = 0\) unless shifted; in this case, based on the point (0, -2), we can deduce that the horizontal asymptote is at \(y = -2\).
Answered by GPT-4o mini
Given the equation of the exponential decay function:

\[
y = 5(0.3)^x - 7
\]

we can analyze its properties, including the horizontal asymptote.

### Properties of the Function

1. **General Form**: This function is of the form:
\[
y = a \cdot b^x + k
\]
where:
- \(a = 5\) (the initial value),
- \(b = 0.3\) (the base, indicating a decay since \(0 < b < 1\)),
- \(k = -7\) (the vertical shift).

2. **Behavior**:
- As \(x\) increases (i.e., as \(x \to \infty\)), the term \(5(0.3)^x\) approaches 0. This is because \(0.3^x\) decreases towards 0 as \(x\) gets larger.
- Thus, the function approaches:
\[
y = 0 - 7 = -7
\]
- As \(x\) decreases (i.e., as \(x \to -\infty\)), \(5(0.3)^x\) becomes very large since \(0.3^x\) grows without bound.

3. **Horizontal Asymptote**:
The horizontal asymptote is the value that the function approaches as \(x\) becomes very large. Therefore, the horizontal asymptote for this function is:
\[
y = -7
\]

### Summary

- **Initial Value**: The function starts at \(y = 5(0.3)^0 - 7 = 5 - 7 = -2\) when \(x = 0\).
- **Decay**: The function decreases as \(x\) increases due to the decay factor of 0.3.
- **Horizontal Asymptote**: The horizontal asymptote of the graph is:
\[
y = -7
\]

This means that as \(x\) approaches infinity, the graph will get closer and closer to the line \(y = -7\).

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