Let's denote the number of visits as \( x \).
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For the first plan, the total cost for \( x \) visits is: \[ \text{Cost}_{\text{Plan 1}} = 10x \]
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For the second plan, the total cost for \( x \) visits is: \[ \text{Cost}_{\text{Plan 2}} = 30 + 4x \]
We need to find the number of visits \( x \) where both plans cost the same: \[ 10x = 30 + 4x \]
Now, we can solve for \( x \).
First, subtract \( 4x \) from both sides: \[ 10x - 4x = 30 \] \[ 6x = 30 \]
Now, divide both sides by 6: \[ x = 5 \]
Thus, the plans would cost the same at 5 visits.